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1301105471 is a prime number
BaseRepresentation
bin100110110001101…
…0100101100111111
310100200021000011112
41031203110230333
510131040333341
6333035112235
744146133261
oct11543245477
93320230145
101301105471
11608492886
123038a267b
131797341c3
14c4b2bb31
157935caeb
hex4d8d4b3f

1301105471 has 2 divisors, whose sum is σ = 1301105472. Its totient is φ = 1301105470.

The previous prime is 1301105461. The next prime is 1301105473. The reversal of 1301105471 is 1745011031.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1301105471 - 222 = 1296911167 is a prime.

It is a super-3 number, since 3×13011054713 (a number of 28 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 1301105473, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1301105473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650552735 + 650552736.

It is an arithmetic number, because the mean of its divisors is an integer number (650552736).

Almost surely, 21301105471 is an apocalyptic number.

1301105471 is a deficient number, since it is larger than the sum of its proper divisors (1).

1301105471 is an equidigital number, since it uses as much as digits as its factorization.

1301105471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 420, while the sum is 23.

The square root of 1301105471 is about 36070.8396215004. The cubic root of 1301105471 is about 1091.7021552034.

The spelling of 1301105471 in words is "one billion, three hundred one million, one hundred five thousand, four hundred seventy-one".