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13011319 is a prime number
BaseRepresentation
bin110001101000…
…100101110111
3220111001011201
4301220211313
511312330234
61142513331
7215410606
oct61504567
926431151
1013011319
117387662
124435847
132907409
141a29a3d
151220314
hexc68977

13011319 has 2 divisors, whose sum is σ = 13011320. Its totient is φ = 13011318.

The previous prime is 13011311. The next prime is 13011337. The reversal of 13011319 is 91311031.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13011319 - 23 = 13011311 is a prime.

It is a super-2 number, since 2×130113192 = 338588844239522, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13011296 and 13011305.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13011311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505659 + 6505660.

It is an arithmetic number, because the mean of its divisors is an integer number (6505660).

Almost surely, 213011319 is an apocalyptic number.

13011319 is a deficient number, since it is larger than the sum of its proper divisors (1).

13011319 is an equidigital number, since it uses as much as digits as its factorization.

13011319 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 19.

The square root of 13011319 is about 3607.1205968196. The cubic root of 13011319 is about 235.2016919430.

It can be divided in two parts, 130 and 11319, that multiplied together give a triangular number (1471470 = T1715).

The spelling of 13011319 in words is "thirteen million, eleven thousand, three hundred nineteen".