Search a number
-
+
130118400 = 283452251
BaseRepresentation
bin1111100000101…
…11001100000000
3100001211200220000
413300113030000
5231302242100
620524520000
73136662636
oct760271400
9301750800
10130118400
11674a2975
12376b0000
1320c5a649
14133d1356
15b653900
hex7c17300

130118400 has 270 divisors, whose sum is σ = 483023772. Its totient is φ = 34560000.

The previous prime is 130118399. The next prime is 130118431. The reversal of 130118400 is 4811031.

It is a tau number, because it is divible by the number of its divisors (270).

It is a hoax number, since the sum of its digits (18) coincides with the sum of the digits of its distinct prime factors.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 29 ways as a sum of consecutive naturals, for example, 518275 + ... + 518525.

Almost surely, 2130118400 is an apocalyptic number.

130118400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130118400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (241511886).

130118400 is an abundant number, since it is smaller than the sum of its proper divisors (352905372).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130118400 is an equidigital number, since it uses as much as digits as its factorization.

130118400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 289 (or 261 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

The square root of 130118400 is about 11406.9452527835. The cubic root of 130118400 is about 506.7334476457.

Adding to 130118400 its reverse (4811031), we get a palindrome (134929431).

It can be divided in two parts, 1301 and 18400, that added together give a triangular number (19701 = T198).

The spelling of 130118400 in words is "one hundred thirty million, one hundred eighteen thousand, four hundred".