Base | Representation |
---|---|
bin | 11000001111001100… |
… | …00010010110111111 |
3 | 1020120211222000110100 |
4 | 30013212002112333 |
5 | 203122123013120 |
6 | 5551111012143 |
7 | 640312561104 |
oct | 140746022677 |
9 | 36524860410 |
10 | 13012313535 |
11 | 5578125831 |
12 | 263196a053 |
13 | 12c4ac3610 |
14 | 8b6252aab |
15 | 512585490 |
hex | 3079825bf |
13012313535 has 48 divisors (see below), whose sum is σ = 24424047648. Its totient is φ = 6370617600.
The previous prime is 13012313473. The next prime is 13012313537. The reversal of 13012313535 is 53531321031.
13012313535 is a `hidden beast` number, since 1 + 3 + 0 + 123 + 1 + 3 + 535 = 666.
It is not a de Polignac number, because 13012313535 - 27 = 13012313407 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13012313499 and 13012313508.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13012313537) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 44440 + ... + 167330.
It is an arithmetic number, because the mean of its divisors is an integer number (508834326).
Almost surely, 213012313535 is an apocalyptic number.
13012313535 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13012313535 is a deficient number, since it is larger than the sum of its proper divisors (11411734113).
13012313535 is a wasteful number, since it uses less digits than its factorization.
13012313535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 123096 (or 123093 counting only the distinct ones).
The product of its (nonzero) digits is 4050, while the sum is 27.
Adding to 13012313535 its reverse (53531321031), we get a palindrome (66543634566).
The spelling of 13012313535 in words is "thirteen billion, twelve million, three hundred thirteen thousand, five hundred thirty-five".
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