130131012211200 has 2880 divisors, whose sum is σ = 634649721818112. Its totient is φ = 24586194124800.

The previous prime is 130131012211171. The next prime is 130131012211241. The reversal of 130131012211200 is 2112210131031.

130131012211200 is a `hidden beast` number, since 1 + 30 + 1 + 310 + 122 + 1 + 1 + 200 = 666.

It is a tau number, because it is divible by the number of its divisors (2880).

It is a super-3 number, since 3×130131012211200³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 287 ways as a sum of consecutive naturals, for example, 7726109979 + ... + 7726126821.

Almost surely, 2^{130131012211200} is an apocalyptic number.

130131012211200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130131012211200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (317324860909056).

130131012211200 is an abundant number, since it is smaller than the sum of its proper divisors (504518709606912).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130131012211200 is a wasteful number, since it uses less digits than its factorization.

130131012211200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16975 (or 16951 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 130131012211200 its reverse (2112210131031), we get a palindrome (132243222342231).

The spelling of 130131012211200 in words is "one hundred thirty trillion, one hundred thirty-one billion, twelve million, two hundred eleven thousand, two hundred".