Base | Representation |
---|---|
bin | 111100101000100011… |
… | …1110110110111010110 |
3 | 110110002120011000212220 |
4 | 1321101013312313112 |
5 | 4113132232024420 |
6 | 135452340523210 |
7 | 12256504006533 |
oct | 1712107666726 |
9 | 413076130786 |
10 | 130210033110 |
11 | 50249195113 |
12 | 2129b0b0506 |
13 | c381562791 |
14 | 643333dd8a |
15 | 35c1500840 |
hex | 1e511f6dd6 |
130210033110 has 32 divisors (see below), whose sum is σ = 317168324352. Its totient is φ = 34204426080.
The previous prime is 130210033073. The next prime is 130210033153. The reversal of 130210033110 is 11330012031.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 130210033110.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 32388546 + ... + 32392565.
It is an arithmetic number, because the mean of its divisors is an integer number (9911510136).
Almost surely, 2130210033110 is an apocalyptic number.
130210033110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
130210033110 is an abundant number, since it is smaller than the sum of its proper divisors (186958291242).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130210033110 is a wasteful number, since it uses less digits than its factorization.
130210033110 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 64781188.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 130210033110 its reverse (11330012031), we get a palindrome (141540045141).
The spelling of 130210033110 in words is "one hundred thirty billion, two hundred ten million, thirty-three thousand, one hundred ten".
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