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130212231000 = 23353174754323
BaseRepresentation
bin111100101000101000…
…0001111011101011000
3110110002201021200211020
41321101100033131120
54113133312343000
6135452500002440
712256531462425
oct1712120173530
9413081250736
10130212231000
115024a456455
122129b990420
13c381b51cc7
146433752d4c
1535c17d6ba0
hex1e5140f758

130212231000 has 256 divisors, whose sum is σ = 439320360960. Its totient is φ = 31984793600.

The previous prime is 130212230959. The next prime is 130212231007. The reversal of 130212231000 is 132212031.

It is a super-3 number, since 3×1302122310003 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130212231007) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2369839 + ... + 2424161.

It is an arithmetic number, because the mean of its divisors is an integer number (1716095160).

Almost surely, 2130212231000 is an apocalyptic number.

130212231000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130212231000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (219660180480).

130212231000 is an abundant number, since it is smaller than the sum of its proper divisors (309108129960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130212231000 is a wasteful number, since it uses less digits than its factorization.

130212231000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 54411 (or 54397 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 130212231000 its reverse (132212031), we get a palindrome (130344443031).

It can be divided in two parts, 13021 and 2231000, that added together give a triangular number (2244021 = T2118).

The spelling of 130212231000 in words is "one hundred thirty billion, two hundred twelve million, two hundred thirty-one thousand".