130212232104400 has 60 divisors (see below), whose sum is σ = 312841007028000. Its totient is φ = 52083874003840.

The previous prime is 130212232104379. The next prime is 130212232104407. The reversal of 130212232104400 is 4401232212031.

130212232104400 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a super-3 number, since 3×130212232104400³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130212232104407) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 17457501 + ... + 23773699.

It is an arithmetic number, because the mean of its divisors is an integer number (5214016783800).

Almost surely, 2^{130212232104400} is an apocalyptic number.

130212232104400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

130212232104400 is an abundant number, since it is smaller than the sum of its proper divisors (182628774923600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130212232104400 is a wasteful number, since it uses less digits than its factorization.

130212232104400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6367756 (or 6367745 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 130212232104400 its reverse (4401232212031), we get a palindrome (134613464316431).

The spelling of 130212232104400 in words is "one hundred thirty trillion, two hundred twelve billion, two hundred thirty-two million, one hundred four thousand, four hundred".