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13023111201000 = 233534341037067
BaseRepresentation
bin1011110110000010110111…
…1010101100000011101000
31201002222221000022011221220
42331200231322230003220
53201332312431413000
643410422405502040
72512613556514215
oct275405572540350
951088830264856
1013023111201000
11417108584110a
121563b71711920
137360c6ab0494
143304715bcb0c
15178b636101a0
hexbd82deac0e8

13023111201000 has 64 divisors (see below), whose sum is σ = 40632106956480. Its totient is φ = 3472829652800.

The previous prime is 13023111200989. The next prime is 13023111201011. The reversal of 13023111201000 is 10211132031.

It is a happy number.

13023111201000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (13023111200989) and next prime (13023111201011).

It is a super-2 number, since 2×130231112010002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2170515534 + ... + 2170521533.

It is an arithmetic number, because the mean of its divisors is an integer number (634876671195).

Almost surely, 213023111201000 is an apocalyptic number.

13023111201000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13023111201000 is an abundant number, since it is smaller than the sum of its proper divisors (27608995755480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13023111201000 is a wasteful number, since it uses less digits than its factorization.

13023111201000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4341037091 (or 4341037077 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 13023111201000 its reverse (10211132031), we get a palindrome (13033322333031).

The spelling of 13023111201000 in words is "thirteen trillion, twenty-three billion, one hundred eleven million, two hundred one thousand".

Divisors: 1 2 3 4 5 6 8 10 12 15 20 24 25 30 40 50 60 75 100 120 125 150 200 250 300 375 500 600 750 1000 1500 3000 4341037067 8682074134 13023111201 17364148268 21705185335 26046222402 34728296536 43410370670 52092444804 65115556005 86820741340 104184889608 108525926675 130231112010 173641482680 217051853350 260462224020 325577780025 434103706700 520924448040 542629633375 651155560050 868207413400 1085259266750 1302311120100 1627888900125 2170518533500 2604622240200 3255777800250 4341037067000 6511555600500 13023111201000