130314000432 has 80 divisors (see below), whose sum is σ = 419712636672. Its totient is φ = 33847791360.

The previous prime is 130314000413. The next prime is 130314000433. The reversal of 130314000432 is 234000413031.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a junction number, because it is equal to n+sod(n) for n = 130314000399 and 130314000408.

It is not an unprimeable number, because it can be changed into a prime (130314000433) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17625363 + ... + 17632754.

Almost surely, 2^130314000432 is an apocalyptic number.

130314000432 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

130314000432 is an abundant number, since it is smaller than the sum of its proper divisors (289398636240).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130314000432 is a wasteful number, since it uses less digits than its factorization.

130314000432 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 35258146 (or 35258140 counting only the distinct ones).

The product of its (nonzero) digits is 864, while the sum is 21.

Adding to 130314000432 its reverse (234000413031), we get a palindrome (364314413463).

The spelling of 130314000432 in words is "one hundred thirty billion, three hundred fourteen million, four hundred thirty-two", and thus it is an aban number.