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13031411100 = 22352313737871
BaseRepresentation
bin11000010001011101…
…11000110110011100
31020122011220021101120
430020232320312130
5203142020123400
65553032210540
7640634111121
oct141056706634
936564807346
1013031411100
11558798a044
122638239a50
1312c8a4c056
148b89c4748
155140a8ca0
hex308bb8d9c

13031411100 has 144 divisors (see below), whose sum is σ = 39973441536. Its totient is φ = 3271968000.

The previous prime is 13031411089. The next prime is 13031411111. The reversal of 13031411100 is 111413031.

13031411100 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (13031411089) and next prime (13031411111).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 13031411100.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 325165 + ... + 363035.

It is an arithmetic number, because the mean of its divisors is an integer number (277593344).

Almost surely, 213031411100 is an apocalyptic number.

13031411100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13031411100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19986720768).

13031411100 is an abundant number, since it is smaller than the sum of its proper divisors (26942030436).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13031411100 is a wasteful number, since it uses less digits than its factorization.

13031411100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37956 (or 37949 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 13031411100 its reverse (111413031), we get a palindrome (13142824131).

The spelling of 13031411100 in words is "thirteen billion, thirty-one million, four hundred eleven thousand, one hundred".

Divisors: 1 2 3 4 5 6 10 12 15 20 25 30 31 37 50 60 62 74 75 93 100 111 124 148 150 155 185 186 222 300 310 370 372 444 465 555 620 740 775 925 930 1110 1147 1550 1850 1860 2220 2294 2325 2775 3100 3441 3700 4588 4650 5550 5735 6882 9300 11100 11470 13764 17205 22940 28675 34410 37871 57350 68820 75742 86025 113613 114700 151484 172050 189355 227226 344100 378710 454452 568065 757420 946775 1136130 1174001 1401227 1893550 2272260 2348002 2802454 2840325 3522003 3787100 4203681 4696004 5604908 5680650 5870005 7006135 7044006 8407362 11361300 11740010 14012270 14088012 16814724 17610015 21018405 23480020 28024540 29350025 35030675 35220030 42036810 43438037 58700050 70061350 70440060 84073620 86876074 88050075 105092025 117400100 130314111 140122700 173752148 176100150 210184050 217190185 260628222 352200300 420368100 434380370 521256444 651570555 868760740 1085950925 1303141110 2171901850 2606282220 3257852775 4343803700 6515705550 13031411100