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130323101103 = 32131113872659
BaseRepresentation
bin111100101011111011…
…1001011010110101111
3110110101102220111000100
41321113313023112233
54113400203213403
6135511500202143
712262346040036
oct1712767132657
9413342814010
10130323101103
11502a6aa1838
1221310b39353
13c39bb00410
14644437371d
1535cb3d72a3
hex1e57dcb5af

130323101103 has 12 divisors (see below), whose sum is σ = 202724824120. Its totient is φ = 80198831376.

The previous prime is 130323101089. The next prime is 130323101173. The reversal of 130323101103 is 301101323031.

It is a happy number.

It is not a de Polignac number, because 130323101103 - 225 = 130289546671 is a prime.

It is a super-2 number, since 2×1303231011032 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130323101173) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 556936213 + ... + 556936446.

Almost surely, 2130323101103 is an apocalyptic number.

130323101103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

130323101103 is a deficient number, since it is larger than the sum of its proper divisors (72401723017).

130323101103 is a wasteful number, since it uses less digits than its factorization.

130323101103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1113872678 (or 1113872675 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 18.

Adding to 130323101103 its reverse (301101323031), we get a palindrome (431424424134).

The spelling of 130323101103 in words is "one hundred thirty billion, three hundred twenty-three million, one hundred one thousand, one hundred three".

Divisors: 1 3 9 13 39 117 1113872659 3341617977 10024853931 14480344567 43441033701 130323101103