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130330011121310 = 25711131713947911503
BaseRepresentation
bin11101101000100011010010…
…000001000011011010011110
3122002110102112120011020110102
4131220203102001003122132
5114040311330321340220
61141104440333341102
736311014113022460
oct3550432201033236
9562412476136412
10130330011121310
1138588713644120
121274a9b5037792
1357950b4b70c30
142428013002130
1510102b182b775
hex7688d204369e

130330011121310 has 512 divisors, whose sum is σ = 336637447372800. Its totient is φ = 34961722122240.

The previous prime is 130330011121253. The next prime is 130330011121339. The reversal of 130330011121310 is 13121110033031.

It is a super-2 number, since 2×1303300111213102 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 11330083019 + ... + 11330094521.

It is an arithmetic number, because the mean of its divisors is an integer number (657495014400).

Almost surely, 2130330011121310 is an apocalyptic number.

130330011121310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

130330011121310 is an abundant number, since it is smaller than the sum of its proper divisors (206307436251490).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130330011121310 is a wasteful number, since it uses less digits than its factorization.

130330011121310 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12176.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 130330011121310 its reverse (13121110033031), we get a palindrome (143451121154341).

The spelling of 130330011121310 in words is "one hundred thirty trillion, three hundred thirty billion, eleven million, one hundred twenty-one thousand, three hundred ten".