Base | Representation |
---|---|
bin | 11101101001100101100101… |
… | …010101001011010100000000 |
3 | 122002201020021222120212220221 |
4 | 131221211211111023110000 |
5 | 114042443130220432112 |
6 | 1141201252451512424 |
7 | 36316114231405330 |
oct | 3551454525132400 |
9 | 562636258525827 |
10 | 130401202124032 |
11 | 38605926057164 |
12 | 127607628b8714 |
13 | 579ba1bc7c708 |
14 | 242b647c850c0 |
15 | 101207b79be07 |
hex | 76996554b500 |
130401202124032 has 72 divisors (see below), whose sum is σ = 297481311288000. Its totient is φ = 55885558996992.
The previous prime is 130401202123991. The next prime is 130401202124051. The reversal of 130401202124032 is 230421202104031.
It is a junction number, because it is equal to n+sod(n) for n = 130401202123988 and 130401202124006.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 166855719 + ... + 167635417.
It is an arithmetic number, because the mean of its divisors is an integer number (4131684879000).
Almost surely, 2130401202124032 is an apocalyptic number.
It is an amenable number.
130401202124032 is an abundant number, since it is smaller than the sum of its proper divisors (167080109163968).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130401202124032 is an frugal number, since it uses more digits than its factorization.
130401202124032 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 873051 (or 873037 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 130401202124032 its reverse (230421202104031), we get a palindrome (360822404228063).
The spelling of 130401202124032 in words is "one hundred thirty trillion, four hundred one billion, two hundred two million, one hundred twenty-four thousand, thirty-two".
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