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130432314012 = 2237111337293473
BaseRepresentation
bin111100101111001011…
…1110010101010011100
3110110200001102001221220
41321132113302222130
54114111133022022
6135530401053340
712265143243030
oct1713627625234
9413601361856
10130432314012
1150352706040
1221341627250
13c3b861b440
146454a821c0
1535d5cab85c
hex1e5e5f2a9c

130432314012 has 192 divisors, whose sum is σ = 419672515584. Its totient is φ = 30427176960.

The previous prime is 130432313983. The next prime is 130432314013. The reversal of 130432314012 is 210413234031.

It is a happy number.

It is a super-2 number, since 2×1304323140122 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130432314013) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 297708 + ... + 591180.

It is an arithmetic number, because the mean of its divisors is an integer number (2185794352).

Almost surely, 2130432314012 is an apocalyptic number.

130432314012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130432314012, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (209836257792).

130432314012 is an abundant number, since it is smaller than the sum of its proper divisors (289240201572).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130432314012 is a wasteful number, since it uses less digits than its factorization.

130432314012 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 293548 (or 293546 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 130432314012 its reverse (210413234031), we get a palindrome (340845548043).

It can be divided in two parts, 130432 and 314012, that added together give a palindrome (444444).

The spelling of 130432314012 in words is "one hundred thirty billion, four hundred thirty-two million, three hundred fourteen thousand, twelve".