Base | Representation |
---|---|
bin | 11101101010000011010100… |
… | …111111011011001100111100 |
3 | 122002211021201210210100020211 |
4 | 131222003110333123030330 |
5 | 114044004032400204322 |
6 | 1141224054000322204 |
7 | 36321324544050514 |
oct | 3552032477331474 |
9 | 562737653710224 |
10 | 130433140241212 |
11 | 38618425310326 |
12 | 12766996913364 |
13 | 57a1a3ba32bc3 |
14 | 242cdd787a844 |
15 | 1012cea612b77 |
hex | 76a0d4fdb33c |
130433140241212 has 48 divisors (see below), whose sum is σ = 241653054488832. Its totient is φ = 61475797011200.
The previous prime is 130433140241197. The next prime is 130433140241311. The reversal of 130433140241212 is 212142041334031.
It is a happy number.
130433140241212 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 18236398 + ... + 24360469.
It is an arithmetic number, because the mean of its divisors is an integer number (5034438635184).
Almost surely, 2130433140241212 is an apocalyptic number.
It is an amenable number.
130433140241212 is a deficient number, since it is larger than the sum of its proper divisors (111219914247620).
130433140241212 is a wasteful number, since it uses less digits than its factorization.
130433140241212 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 42597378 (or 42597376 counting only the distinct ones).
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 130433140241212 its reverse (212142041334031), we get a palindrome (342575181575243).
The spelling of 130433140241212 in words is "one hundred thirty trillion, four hundred thirty-three billion, one hundred forty million, two hundred forty-one thousand, two hundred twelve".
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