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13044000323440 = 245163050004043
BaseRepresentation
bin1011110111010000101100…
…0000010111011101110000
31201011222211210212112220101
42331310023000113131300
53202203103040322230
643424155300122144
72514253326233632
oct275641300273560
951158753775811
1013044000323440
114179a25142a69
121568021396354
13738075743668
143314939cca52
15179487459aca
hexbdd0b017770

13044000323440 has 20 divisors (see below), whose sum is σ = 30327300752184. Its totient is φ = 5217600129344.

The previous prime is 13044000323413. The next prime is 13044000323467. The reversal of 13044000323440 is 4432300044031.

13044000323440 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (13044000323413) and next prime (13044000323467).

It is a tau number, because it is divible by the number of its divisors (20).

It is a super-2 number, since 2×130440003234402 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13044000323399 and 13044000323408.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81525001942 + ... + 81525002101.

Almost surely, 213044000323440 is an apocalyptic number.

13044000323440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13044000323440 is an abundant number, since it is smaller than the sum of its proper divisors (17283300428744).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13044000323440 is a wasteful number, since it uses less digits than its factorization.

13044000323440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 163050004056 (or 163050004050 counting only the distinct ones).

The product of its (nonzero) digits is 13824, while the sum is 28.

Adding to 13044000323440 its reverse (4432300044031), we get a palindrome (17476300367471).

The spelling of 13044000323440 in words is "thirteen trillion, forty-four billion, three hundred twenty-three thousand, four hundred forty".

Divisors: 1 2 4 5 8 10 16 20 40 80 163050004043 326100008086 652200016172 815250020215 1304400032344 1630500040430 2608800064688 3261000080860 6522000161720 13044000323440