130440020402421 has 12 divisors (see below), whose sum is σ = 199496501792172. Its totient is φ = 81844718683776.

The previous prime is 130440020402389. The next prime is 130440020402423. The reversal of 130440020402421 is 124204020044031.

130440020402421 is a `hidden beast` number, since 1 + 30 + 4 + 4 + 0 + 0 + 204 + 0 + 2 + 421 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 111344999456196 + 19095020946225 = 10552014^2 + 4369785^2 .

It is not a de Polignac number, because 130440020402421 - 2⁵ = 130440020402389 is a prime.

It is a super-2 number, since 2×130440020402421² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130440020402423) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 426274576326 + ... + 426274576631.

It is an arithmetic number, because the mean of its divisors is an integer number (16624708482681).

Almost surely, 2^{130440020402421} is an apocalyptic number.

It is an amenable number.

130440020402421 is a deficient number, since it is larger than the sum of its proper divisors (69056481389751).

130440020402421 is a wasteful number, since it uses less digits than its factorization.

130440020402421 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 852549152980 (or 852549152977 counting only the distinct ones).

The product of its (nonzero) digits is 6144, while the sum is 27.

Adding to 130440020402421 its reverse (124204020044031), we get a palindrome (254644040446452).

The spelling of 130440020402421 in words is "one hundred thirty trillion, four hundred forty billion, twenty million, four hundred two thousand, four hundred twenty-one".