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13044002400 = 253352111341103
BaseRepresentation
bin11000010010111101…
…11010111001100000
31020200001120222102000
430021132322321200
5203203231034100
65554202124000
7641146122342
oct141136727140
936601528360
1013044002400
115593aaa080
1226404b0600
1312cb53a220
148ba541292
15515244900
hex3097bae60

13044002400 has 1152 divisors, whose sum is σ = 57326330880. Its totient is φ = 2820096000.

The previous prime is 13044002393. The next prime is 13044002407. The reversal of 13044002400 is 420044031.

13044002400 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (13044002393) and next prime (13044002407).

It is a super-2 number, since 2×130440024002 (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13044002407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 126640749 + ... + 126640851.

It is an arithmetic number, because the mean of its divisors is an integer number (49762440).

Almost surely, 213044002400 is an apocalyptic number.

13044002400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13044002400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (28663165440).

13044002400 is an abundant number, since it is smaller than the sum of its proper divisors (44282328480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13044002400 is a wasteful number, since it uses less digits than its factorization.

13044002400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 197 (or 178 counting only the distinct ones).

The product of its (nonzero) digits is 384, while the sum is 18.

Adding to 13044002400 its reverse (420044031), we get a palindrome (13464046431).

The spelling of 13044002400 in words is "thirteen billion, forty-four million, two thousand, four hundred".