Base | Representation |
---|---|
bin | 1011110111010010100011… |
… | …0100000011101001001101 |
3 | 1201012001010122212201211010 |
4 | 2331310220310003221031 |
5 | 3202210114101204010 |
6 | 43424321042515433 |
7 | 2514301611022665 |
oct | 275645064035115 |
9 | 51161118781733 |
10 | 13044500413005 |
11 | 417a161460726 |
12 | 1568140965b79 |
13 | 73812522a449 |
14 | 3315001a91a5 |
15 | 1794b62de620 |
hex | bdd28d03a4d |
13044500413005 has 16 divisors (see below), whose sum is σ = 21182711120064. Its totient is φ = 6853230067200.
The previous prime is 13044500412973. The next prime is 13044500413031. The reversal of 13044500413005 is 50031400544031.
13044500413005 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13044500413005 - 25 = 13044500412973 is a prime.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6489800196 + ... + 6489802205.
It is an arithmetic number, because the mean of its divisors is an integer number (1323919445004).
Almost surely, 213044500413005 is an apocalyptic number.
13044500413005 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13044500413005 is a deficient number, since it is larger than the sum of its proper divisors (8138210707059).
13044500413005 is a wasteful number, since it uses less digits than its factorization.
13044500413005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12979602476.
The product of its (nonzero) digits is 14400, while the sum is 30.
Adding to 13044500413005 its reverse (50031400544031), we get a palindrome (63075900957036).
The spelling of 13044500413005 in words is "thirteen trillion, forty-four billion, five hundred million, four hundred thirteen thousand, five".
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