Base | Representation |
---|---|
bin | 11000010011101110… |
… | …10101100010111000 |
3 | 1020200111122011101021 |
4 | 30021313111202320 |
5 | 203211400344000 |
6 | 5554551232224 |
7 | 641254411105 |
oct | 141167254270 |
9 | 36614564337 |
10 | 13050403000 |
11 | 5597680a28 |
12 | 2642678674 |
13 | 12cc96b66b |
14 | 8bb329aac |
15 | 515aab11a |
hex | 309dd58b8 |
13050403000 has 32 divisors (see below), whose sum is σ = 30537945360. Its totient is φ = 5220160800.
The previous prime is 13050402997. The next prime is 13050403001. The reversal of 13050403000 is 30405031.
13050403000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13050403001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6524202 + ... + 6526201.
Almost surely, 213050403000 is an apocalyptic number.
13050403000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13050403000 is an abundant number, since it is smaller than the sum of its proper divisors (17487542360).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13050403000 is a wasteful number, since it uses less digits than its factorization.
13050403000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13050424 (or 13050410 counting only the distinct ones).
The product of its (nonzero) digits is 180, while the sum is 16.
Adding to 13050403000 its reverse (30405031), we get a palindrome (13080808031).
The spelling of 13050403000 in words is "thirteen billion, fifty million, four hundred three thousand".
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