Base | Representation |
---|---|
bin | 10010111111110000000… |
… | …101110011000101111000 |
3 | 11121210110210022112100210 |
4 | 102333300011303011320 |
5 | 132341431201030040 |
6 | 2435405515431120 |
7 | 163212051426441 |
oct | 22776005630570 |
9 | 4553423275323 |
10 | 1305403142520 |
11 | 463689051134 |
12 | 190bb4a554a0 |
13 | 96139627aa9 |
14 | 47278dcc2c8 |
15 | 23e53461480 |
hex | 12ff0173178 |
1305403142520 has 64 divisors (see below), whose sum is σ = 3916935659520. Its totient is φ = 348042950784.
The previous prime is 1305403142513. The next prime is 1305403142539. The reversal of 1305403142520 is 252413045031.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 357112 + ... + 1654791.
It is an arithmetic number, because the mean of its divisors is an integer number (61202119680).
Almost surely, 21305403142520 is an apocalyptic number.
1305403142520 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1305403142520 is an abundant number, since it is smaller than the sum of its proper divisors (2611532517000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1305403142520 is a wasteful number, since it uses less digits than its factorization.
1305403142520 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2017324 (or 2017320 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 30.
Adding to 1305403142520 its reverse (252413045031), we get a palindrome (1557816187551).
The spelling of 1305403142520 in words is "one trillion, three hundred five billion, four hundred three million, one hundred forty-two thousand, five hundred twenty".
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