13055011303 has 4 divisors (see below), whose sum is σ = 13057328800. Its totient is φ = 13052693808.

The previous prime is 13055011279. The next prime is 13055011313. The reversal of 13055011303 is 30311055031.

13055011303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30311055031 = 409 ⋅74110159.

It is a cyclic number.

It is not a de Polignac number, because 13055011303 - 2⁵ = 13055011271 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13055011313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1150278 + ... + 1161571.

It is an arithmetic number, because the mean of its divisors is an integer number (3264332200).

Almost surely, 2^13055011303 is an apocalyptic number.

13055011303 is a deficient number, since it is larger than the sum of its proper divisors (2317497).

13055011303 is an equidigital number, since it uses as much as digits as its factorization.

13055011303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2317496.

The product of its (nonzero) digits is 675, while the sum is 22.

Adding to 13055011303 its reverse (30311055031), we get a palindrome (43366066334).

The spelling of 13055011303 in words is "thirteen billion, fifty-five million, eleven thousand, three hundred three".