131000024412 has 60 divisors (see below), whose sum is σ = 342806350656. Its totient is φ = 43622504640.

The previous prime is 131000024383. The next prime is 131000024417. The reversal of 131000024412 is 214420000131.

It is a super-2 number, since 2×131000024412² (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131000024417) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 117088 + ... + 525080.

Almost surely, 2^131000024412 is an apocalyptic number.

131000024412 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

131000024412 is an abundant number, since it is smaller than the sum of its proper divisors (211806326244).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131000024412 is a wasteful number, since it uses less digits than its factorization.

131000024412 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 409000 (or 408989 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 18.

Adding to 131000024412 its reverse (214420000131), we get a palindrome (345420024543).

The spelling of 131000024412 in words is "one hundred thirty-one billion, twenty-four thousand, four hundred twelve".