Base | Representation |
---|---|
bin | 11101110010010011011100… |
… | …101000000101010101001000 |
3 | 122011211111102110100011100102 |
4 | 131302103130220011111020 |
5 | 114132301404212214422 |
6 | 1142340355105224532 |
7 | 36410311114502204 |
oct | 3562233450052510 |
9 | 564744373304312 |
10 | 131000204023112 |
11 | 38816969003766 |
12 | 12838873332148 |
13 | 581335cbb6258 |
14 | 244c62d753b04 |
15 | 1022938bb1192 |
hex | 7724dca05548 |
131000204023112 has 8 divisors (see below), whose sum is σ = 245625382543350. Its totient is φ = 65500102011552.
The previous prime is 131000204023111. The next prime is 131000204023177. The reversal of 131000204023112 is 211320402000131.
It can be written as a sum of positive squares in only one way, i.e., 128577592710436 + 2422611312676 = 11339206^2 + 1556474^2 .
It is a tau number, because it is divible by the number of its divisors (8).
It is a super-2 number, since 2×1310002040231122 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (131000204023111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8187512751437 + ... + 8187512751452.
Almost surely, 2131000204023112 is an apocalyptic number.
It is an amenable number.
131000204023112 is a deficient number, since it is larger than the sum of its proper divisors (114625178520238).
131000204023112 is a wasteful number, since it uses less digits than its factorization.
131000204023112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16375025502895 (or 16375025502891 counting only the distinct ones).
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 131000204023112 its reverse (211320402000131), we get a palindrome (342320606023243).
The spelling of 131000204023112 in words is "one hundred thirty-one trillion, two hundred four million, twenty-three thousand, one hundred twelve".
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