131000333020400 has 120 divisors (see below), whose sum is σ = 317311159785984. Its totient is φ = 51970376908800.

The previous prime is 131000333020397. The next prime is 131000333020451. The reversal of 131000333020400 is 4020333000131.

It is a super-2 number, since 2×131000333020400² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 154058804 + ... + 154906796.

Almost surely, 2^{131000333020400} is an apocalyptic number.

131000333020400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131000333020400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (158655579892992).

131000333020400 is an abundant number, since it is smaller than the sum of its proper divisors (186310826765584).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131000333020400 is a wasteful number, since it uses less digits than its factorization.

131000333020400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 851179 (or 851168 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 20.

Adding to 131000333020400 its reverse (4020333000131), we get a palindrome (135020666020531).

The spelling of 131000333020400 in words is "one hundred thirty-one trillion, three hundred thirty-three million, twenty thousand, four hundred".