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131000421130120 = 2353275010528253
BaseRepresentation
bin11101110010010011101001…
…100100010001111110001000
3122011211111222120212100011201
4131302103221210101332020
5114132302330302130440
61142340432422433544
736410316362046223
oct3562235144217610
9564744876770151
10131000421130120
1138816a6a610443
1212838913b928b4
135813395b7cc39
14244c65050a5ba
15102294cc9919a
hex7724e9911f88

131000421130120 has 16 divisors (see below), whose sum is σ = 294750947542860. Its totient is φ = 52400168452032.

The previous prime is 131000421129971. The next prime is 131000421130129. The reversal of 131000421130120 is 21031124000131.

It can be written as a sum of positive squares in 2 ways, for example, as 124177636824004 + 6822784306116 = 11143502^2 + 2612046^2 .

It is a super-3 number, since 3×1310004211301203 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (131000421130129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1637505264087 + ... + 1637505264166.

Almost surely, 2131000421130120 is an apocalyptic number.

131000421130120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131000421130120 is an abundant number, since it is smaller than the sum of its proper divisors (163750526412740).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131000421130120 is a wasteful number, since it uses less digits than its factorization.

131000421130120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3275010528264 (or 3275010528260 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 131000421130120 its reverse (21031124000131), we get a palindrome (152031545130251).

The spelling of 131000421130120 in words is "one hundred thirty-one trillion, four hundred twenty-one million, one hundred thirty thousand, one hundred twenty".

Divisors: 1 2 4 5 8 10 20 40 3275010528253 6550021056506 13100042113012 16375052641265 26200084226024 32750105282530 65500210565060 131000421130120