Base | Representation |
---|---|
bin | 11101110010010100100000… |
… | …010110010011010000010000 |
3 | 122011211121100122021112211020 |
4 | 131302110200112103100100 |
5 | 114132311221043242430 |
6 | 1142341103533515440 |
7 | 36410351222112021 |
oct | 3562244026232020 |
9 | 564747318245736 |
10 | 131001340212240 |
11 | 388173a1396443 |
12 | 12838b2b942b80 |
13 | 58134b13c8004 |
14 | 244c6da5d2c48 |
15 | 10229a37e4b10 |
hex | 772520593410 |
131001340212240 has 80 divisors (see below), whose sum is σ = 406107142354368. Its totient is φ = 34933433717248.
The previous prime is 131001340212181. The next prime is 131001340212247. The reversal of 131001340212240 is 42212043100131.
It is a tau number, because it is divible by the number of its divisors (80).
It is a super-2 number, since 2×1310013402122402 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a self number, because there is not a number n which added to its sum of digits gives 131001340212240.
It is not an unprimeable number, because it can be changed into a prime (131001340212247) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 31870654 + ... + 35745506.
Almost surely, 2131001340212240 is an apocalyptic number.
131001340212240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131001340212240 is an abundant number, since it is smaller than the sum of its proper divisors (275105802142128).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131001340212240 is a wasteful number, since it uses less digits than its factorization.
131001340212240 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4015736 (or 4015730 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 131001340212240 its reverse (42212043100131), we get a palindrome (173213383312371).
The spelling of 131001340212240 in words is "one hundred thirty-one trillion, one billion, three hundred forty million, two hundred twelve thousand, two hundred forty".
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