131001401442340 has 192 divisors, whose sum is σ = 332814201753600. Its totient is φ = 42675383808000.

The previous prime is 131001401442287. The next prime is 131001401442383. The reversal of 131001401442340 is 43244104100131.

It is a super-2 number, since 2×131001401442340² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131001401442299 and 131001401442308.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 19472086 + ... + 25321234.

It is an arithmetic number, because the mean of its divisors is an integer number (1733407300800).

Almost surely, 2^{131001401442340} is an apocalyptic number.

131001401442340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131001401442340, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (166407100876800).

131001401442340 is an abundant number, since it is smaller than the sum of its proper divisors (201812800311260).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131001401442340 is a wasteful number, since it uses less digits than its factorization.

131001401442340 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5849414 (or 5849412 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 131001401442340 its reverse (43244104100131), we get a palindrome (174245505542471).

The spelling of 131001401442340 in words is "one hundred thirty-one trillion, one billion, four hundred one million, four hundred forty-two thousand, three hundred forty".