Base | Representation |
---|---|
bin | 111101000000001011… |
… | …0001100010010011111 |
3 | 110112010202222101012221 |
4 | 1322000112030102133 |
5 | 4121243043220111 |
6 | 140103122210211 |
7 | 12315234230122 |
oct | 1720026142237 |
9 | 415122871187 |
10 | 131002320031 |
11 | 50615437aa0 |
12 | 214804b3967 |
13 | c4797449cb |
14 | 64aa65c3b9 |
15 | 361ad52371 |
hex | 1e8058c49f |
131002320031 has 8 divisors (see below), whose sum is σ = 150433286400. Its totient is φ = 112824964440.
The previous prime is 131002320019. The next prime is 131002320041. The reversal of 131002320031 is 130023200131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131002320031 - 211 = 131002317983 is a prime.
It is a super-2 number, since 2×1310023200312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131002319987 and 131002320014.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131002320041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 313402471 + ... + 313402888.
It is an arithmetic number, because the mean of its divisors is an integer number (18804160800).
Almost surely, 2131002320031 is an apocalyptic number.
131002320031 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
131002320031 is a deficient number, since it is larger than the sum of its proper divisors (19430966369).
131002320031 is a wasteful number, since it uses less digits than its factorization.
131002320031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 626805389.
The product of its (nonzero) digits is 108, while the sum is 16.
Adding to 131002320031 its reverse (130023200131), we get a palindrome (261025520162).
The spelling of 131002320031 in words is "one hundred thirty-one billion, two million, three hundred twenty thousand, thirty-one".
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