131003111320 has 16 divisors (see below), whose sum is σ = 294757000560. Its totient is φ = 52401244512.

The previous prime is 131003111299. The next prime is 131003111333. The reversal of 131003111320 is 23111300131.

It is a junction number, because it is equal to n+sod(n) for n = 131003111294 and 131003111303.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1637538852 + ... + 1637538931.

It is an arithmetic number, because the mean of its divisors is an integer number (18422312535).

Almost surely, 2^131003111320 is an apocalyptic number.

131003111320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131003111320 is an abundant number, since it is smaller than the sum of its proper divisors (163753889240).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131003111320 is a wasteful number, since it uses less digits than its factorization.

131003111320 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3275077794 (or 3275077790 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 131003111320 its reverse (23111300131), we get a palindrome (154114411451).

The spelling of 131003111320 in words is "one hundred thirty-one billion, three million, one hundred eleven thousand, three hundred twenty".