Base | Representation |
---|---|
bin | 11101110010011101100111… |
… | …100001010000011101010100 |
3 | 122011212112121111120200122102 |
4 | 131302131213201100131110 |
5 | 114132441240243420200 |
6 | 1142345402442421232 |
7 | 36411145534463330 |
oct | 3562354741203524 |
9 | 564775544520572 |
10 | 131011124201300 |
11 | 38820562182212 |
12 | 1283aa00501818 |
13 | 58143b0413655 |
14 | 244cd87ba67c0 |
15 | 1022d777346d5 |
hex | 772767850754 |
131011124201300 has 72 divisors (see below), whose sum is σ = 324914233949760. Its totient is φ = 44917180934400.
The previous prime is 131011124201281. The next prime is 131011124201329. The reversal of 131011124201300 is 3102421110131.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 32780915 + ... + 36559685.
Almost surely, 2131011124201300 is an apocalyptic number.
131011124201300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131011124201300 is an abundant number, since it is smaller than the sum of its proper divisors (193903109748460).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131011124201300 is a wasteful number, since it uses less digits than its factorization.
131011124201300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3828321 (or 3828314 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 131011124201300 its reverse (3102421110131), we get a palindrome (134113545311431).
The spelling of 131011124201300 in words is "one hundred thirty-one trillion, eleven billion, one hundred twenty-four million, two hundred one thousand, three hundred".
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