Base | Representation |
---|---|
bin | 111101000000011100… |
… | …0010001010000110100 |
3 | 110112011101210020100202 |
4 | 1322000320101100310 |
5 | 4121302340101200 |
6 | 140104041500032 |
7 | 12315403164464 |
oct | 1720070212064 |
9 | 415141706322 |
10 | 131011253300 |
11 | 5061a489764 |
12 | 214834a1618 |
13 | c47b551b75 |
14 | 64ab905ba4 |
15 | 361ba191d5 |
hex | 1e80e11434 |
131011253300 has 36 divisors (see below), whose sum is σ = 284624032896. Its totient is φ = 52343743200.
The previous prime is 131011253251. The next prime is 131011253311. The reversal of 131011253300 is 3352110131.
It is a super-3 number, since 3×1310112533003 (a number of 34 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 672746 + ... + 845345.
It is an arithmetic number, because the mean of its divisors is an integer number (7906223136).
Almost surely, 2131011253300 is an apocalyptic number.
131011253300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131011253300 is an abundant number, since it is smaller than the sum of its proper divisors (153612779596).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131011253300 is a wasteful number, since it uses less digits than its factorization.
131011253300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1518968 (or 1518961 counting only the distinct ones).
The product of its (nonzero) digits is 270, while the sum is 20.
Adding to 131011253300 its reverse (3352110131), we get a palindrome (134363363431).
The spelling of 131011253300 in words is "one hundred thirty-one billion, eleven million, two hundred fifty-three thousand, three hundred".
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