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131012115 = 35131739521
BaseRepresentation
bin1111100111100…
…01011000010011
3100010112002211120
413303301120103
5232014341430
621000013323
73150404343
oct763613023
9303462746
10131012115
1167a53383
1237a61243
13211b1380
1413584d23
15b77d610
hex7cf1613

131012115 has 32 divisors (see below), whose sum is σ = 239029056. Its totient is φ = 60702720.

The previous prime is 131012113. The next prime is 131012173. The reversal of 131012115 is 511210131.

It is not a de Polignac number, because 131012115 - 21 = 131012113 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a junction number, because it is equal to n+sod(n) for n = 131012094 and 131012103.

It is not an unprimeable number, because it can be changed into a prime (131012113) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 16446 + ... + 23075.

It is an arithmetic number, because the mean of its divisors is an integer number (7469658).

Almost surely, 2131012115 is an apocalyptic number.

131012115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

131012115 is a deficient number, since it is larger than the sum of its proper divisors (108016941).

131012115 is a wasteful number, since it uses less digits than its factorization.

131012115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 39559.

The product of its (nonzero) digits is 30, while the sum is 15.

The square root of 131012115 is about 11446.0523762562. The cubic root of 131012115 is about 507.8909635886.

Adding to 131012115 its reverse (511210131), we get a palindrome (642222246).

The spelling of 131012115 in words is "one hundred thirty-one million, twelve thousand, one hundred fifteen".

Divisors: 1 3 5 13 15 17 39 51 65 85 195 221 255 663 1105 3315 39521 118563 197605 513773 592815 671857 1541319 2015571 2568865 3359285 7706595 8734141 10077855 26202423 43670705 131012115