13102011101 has 2 divisors, whose sum is σ = 13102011102. Its totient is φ = 13102011100.

The previous prime is 13102011067. The next prime is 13102011103. The reversal of 13102011101 is 10111020131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11507925625 + 1594085476 = 107275^2 + 39926^2 .

It is an emirp because it is prime and its reverse (10111020131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13102011101 is a prime.

Together with 13102011103, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13102011103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551005550 + 6551005551.

It is an arithmetic number, because the mean of its divisors is an integer number (6551005551).

Almost surely, 2^13102011101 is an apocalyptic number.

It is an amenable number.

13102011101 is a deficient number, since it is larger than the sum of its proper divisors (1).

13102011101 is an equidigital number, since it uses as much as digits as its factorization.

13102011101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 13102011101 its reverse (10111020131), we get a palindrome (23213031232).

The spelling of 13102011101 in words is "thirteen billion, one hundred two million, eleven thousand, one hundred one".