Base | Representation |
---|---|
bin | 1011111010101000110101… |
… | …1000010000101011000000 |
3 | 1201101112121110021021102111 |
4 | 2332222031120100223000 |
5 | 3204130420140400000 |
6 | 43510552542225104 |
7 | 2521406216112616 |
oct | 276521530205300 |
9 | 51345543237374 |
10 | 13102022200000 |
11 | 41a1599a65668 |
12 | 1577314885194 |
13 | 740691415ab6 |
14 | 3341d987d6b6 |
15 | 17ac311bbcba |
hex | bea8d610ac0 |
13102022200000 has 84 divisors (see below), whose sum is σ = 32497077178944. Its totient is φ = 5240808800000.
The previous prime is 13102022199997. The next prime is 13102022200009. The reversal of 13102022200000 is 222020131.
It is not an unprimeable number, because it can be changed into a prime (13102022200009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 32555056 + ... + 32955055.
It is an arithmetic number, because the mean of its divisors is an integer number (386869966416).
Almost surely, 213102022200000 is an apocalyptic number.
13102022200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13102022200000 is an abundant number, since it is smaller than the sum of its proper divisors (19395054978944).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13102022200000 is an frugal number, since it uses more digits than its factorization.
13102022200000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65510148 (or 65510118 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 13.
Adding to 13102022200000 its reverse (222020131), we get a palindrome (13102244220131).
The spelling of 13102022200000 in words is "thirteen trillion, one hundred two billion, twenty-two million, two hundred thousand".
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