Base | Representation |
---|---|
bin | 1011111010101100011110… |
… | …1011011010101001010000 |
3 | 1201101122010121201220112120 |
4 | 2332223013223122221100 |
5 | 3204134421034100422 |
6 | 43511234002254240 |
7 | 2521442363612502 |
oct | 276530753325120 |
9 | 51348117656476 |
10 | 13103000300112 |
11 | 41a1a51090768 |
12 | 1577548357380 |
13 | 7407b8c55b68 |
14 | 33428d729d72 |
15 | 17ac8bec445c |
hex | beac7adaa50 |
13103000300112 has 80 divisors (see below), whose sum is σ = 35844794661312. Its totient is φ = 4110259456000.
The previous prime is 13103000300111. The next prime is 13103000300119. The reversal of 13103000300112 is 21100300030131.
It is a junction number, because it is equal to n+sod(n) for n = 13103000300091 and 13103000300100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13103000300111) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5992363 + ... + 7881269.
Almost surely, 213103000300112 is an apocalyptic number.
13103000300112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
13103000300112 is an abundant number, since it is smaller than the sum of its proper divisors (22741794361200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13103000300112 is a wasteful number, since it uses less digits than its factorization.
13103000300112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1897436 (or 1897430 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 13103000300112 its reverse (21100300030131), we get a palindrome (34203300330243).
The spelling of 13103000300112 in words is "thirteen trillion, one hundred three billion, three hundred thousand, one hundred twelve".
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