Base | Representation |
---|---|
bin | 1011111010101100100011… |
… | …0110101011110000011000 |
3 | 1201101122011222212100020012 |
4 | 2332223020312223300120 |
5 | 3204134441111443000 |
6 | 43511235545221052 |
7 | 2521443023411114 |
oct | 276531066536030 |
9 | 51348158770205 |
10 | 13103020031000 |
11 | 41a1a61237889 |
12 | 1577552a91788 |
13 | 7407c0073943 |
14 | 3342921c4744 |
15 | 17ac8dac0735 |
hex | beac8dabc18 |
13103020031000 has 96 divisors (see below), whose sum is σ = 30807173348640. Its totient is φ = 5216350440000.
The previous prime is 13103020030897. The next prime is 13103020031099. The reversal of 13103020031000 is 13002030131.
It is a super-2 number, since 2×131030200310002 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 44373845 + ... + 44668155.
It is an arithmetic number, because the mean of its divisors is an integer number (320908055715).
Almost surely, 213103020031000 is an apocalyptic number.
13103020031000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13103020031000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15403586674320).
13103020031000 is an abundant number, since it is smaller than the sum of its proper divisors (17704153317640).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13103020031000 is an equidigital number, since it uses as much as digits as its factorization.
13103020031000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 294754 (or 294529 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 13103020031000 its reverse (13002030131), we get a palindrome (13116022061131).
The spelling of 13103020031000 in words is "thirteen trillion, one hundred three billion, twenty million, thirty-one thousand".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •