Base | Representation |
---|---|
bin | 11101110010110000010101… |
… | …100001010001011011011000 |
3 | 122011221110111020121012112020 |
4 | 131302300111201101123120 |
5 | 114133303421131410130 |
6 | 1142402525112214440 |
7 | 36412456602211104 |
oct | 3562602541213330 |
9 | 564843436535466 |
10 | 131031223310040 |
11 | 38829036644089 |
12 | 1284288b69a420 |
13 | 58162644ac1c1 |
14 | 244dd332ca904 |
15 | 102365202ae10 |
hex | 772c158516d8 |
131031223310040 has 64 divisors (see below), whose sum is σ = 393185451456000. Its totient is φ = 34933501191552.
The previous prime is 131031223310027. The next prime is 131031223310087. The reversal of 131031223310040 is 40013322130131.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 126958240 + ... + 127986159.
It is an arithmetic number, because the mean of its divisors is an integer number (6143522679000).
Almost surely, 2131031223310040 is an apocalyptic number.
131031223310040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131031223310040 is an abundant number, since it is smaller than the sum of its proper divisors (262154228145960).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131031223310040 is a wasteful number, since it uses less digits than its factorization.
131031223310040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 254948696 (or 254948692 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 131031223310040 its reverse (40013322130131), we get a palindrome (171044545440171).
The spelling of 131031223310040 in words is "one hundred thirty-one trillion, thirty-one billion, two hundred twenty-three million, three hundred ten thousand, forty".
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