13103312241245 has 4 divisors (see below), whose sum is σ = 15723974689500. Its totient is φ = 10482649792992.

The previous prime is 13103312241197. The next prime is 13103312241329. The reversal of 13103312241245 is 54214221330131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8535641382724 + 4567670858521 = 2921582^2 + 2137211^2 .

It is a cyclic number.

It is not a de Polignac number, because 13103312241245 - 2¹⁸ = 13103311979101 is a prime.

It is a super-2 number, since 2×13103312241245² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1310331224120 + ... + 1310331224129.

It is an arithmetic number, because the mean of its divisors is an integer number (3930993672375).

Almost surely, 2^{13103312241245} is an apocalyptic number.

It is an amenable number.

13103312241245 is a deficient number, since it is larger than the sum of its proper divisors (2620662448255).

13103312241245 is an equidigital number, since it uses as much as digits as its factorization.

13103312241245 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2620662448254.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 13103312241245 its reverse (54214221330131), we get a palindrome (67317533571376).

The spelling of 13103312241245 in words is "thirteen trillion, one hundred three billion, three hundred twelve million, two hundred forty-one thousand, two hundred forty-five".