1310341534000 has 40 divisors (see below), whose sum is σ = 3168405834048. Its totient is φ = 524136612800.

The previous prime is 1310341533979. The next prime is 1310341534001. The reversal of 1310341534000 is 4351430131.

It is a tau number, because it is divible by the number of its divisors (40).

It is a super-3 number, since 3×1310341534000³ (a number of 37 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is not an unprimeable number, because it can be changed into a prime (1310341534001) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 327583384 + ... + 327587383.

Almost surely, 2^{1310341534000} is an apocalyptic number.

1310341534000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1310341534000 is an abundant number, since it is smaller than the sum of its proper divisors (1858064300048).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1310341534000 is an equidigital number, since it uses as much as digits as its factorization.

1310341534000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 655170790 (or 655170774 counting only the distinct ones).

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 1310341534000 its reverse (4351430131), we get a palindrome (1314692964131).

The spelling of 1310341534000 in words is "one trillion, three hundred ten billion, three hundred forty-one million, five hundred thirty-four thousand".