1310401422041 has 4 divisors (see below), whose sum is σ = 1310404835892. Its totient is φ = 1310398008192.

The previous prime is 1310401422023. The next prime is 1310401422091. The reversal of 1310401422041 is 1402241040131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 105612000400 + 1204789421641 = 324980^2 + 1097629^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310401422041 - 2⁶ = 1310401421977 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1310401421998 and 1310401422016.

It is not an unprimeable number, because it can be changed into a prime (1310401422091) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1045796 + ... + 1927301.

It is an arithmetic number, because the mean of its divisors is an integer number (327601208973).

Almost surely, 2^{1310401422041} is an apocalyptic number.

It is an amenable number.

1310401422041 is a deficient number, since it is larger than the sum of its proper divisors (3413851).

1310401422041 is an equidigital number, since it uses as much as digits as its factorization.

1310401422041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3413850.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 1310401422041 its reverse (1402241040131), we get a palindrome (2712642462172).

The spelling of 1310401422041 in words is "one trillion, three hundred ten billion, four hundred one million, four hundred twenty-two thousand, forty-one".