Base | Representation |
---|---|
bin | 11101110010111011100111… |
… | …010000010011100100110100 |
3 | 122011222121202010021000101210 |
4 | 131302323213100103210310 |
5 | 114134003220443343330 |
6 | 1142412250423521420 |
7 | 36413365633403136 |
oct | 3562734720234464 |
9 | 564877663230353 |
10 | 131043332012340 |
11 | 3883318a6a0370 |
12 | 128450aa8b9270 |
13 | 58174440134c7 |
14 | 2450761523056 |
15 | 1023b100be8b0 |
hex | 772ee7413934 |
131043332012340 has 48 divisors (see below), whose sum is σ = 400277814148800. Its totient is φ = 31768080487680.
The previous prime is 131043332012323. The next prime is 131043332012363. The reversal of 131043332012340 is 43210233340131.
131043332012340 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a junction number, because it is equal to n+sod(n) for n = 131043332012298 and 131043332012307.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 99275250865 + ... + 99275252184.
It is an arithmetic number, because the mean of its divisors is an integer number (8339121128100).
Almost surely, 2131043332012340 is an apocalyptic number.
131043332012340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131043332012340 is an abundant number, since it is smaller than the sum of its proper divisors (269234482136460).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131043332012340 is a wasteful number, since it uses less digits than its factorization.
131043332012340 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 198550503072 (or 198550503070 counting only the distinct ones).
The product of its (nonzero) digits is 15552, while the sum is 30.
Adding to 131043332012340 its reverse (43210233340131), we get a palindrome (174253565352471).
The spelling of 131043332012340 in words is "one hundred thirty-one trillion, forty-three billion, three hundred thirty-two million, twelve thousand, three hundred forty".
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