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1310537606045 = 52332573498919
BaseRepresentation
bin10011000100100010001…
…000001110001110011101
311122021201121201022012112
4103010202020032032131
5132432440111343140
62442015213043405
7163453225565033
oct23044210161635
94567647638175
101310537606045
11465883349618
12191ba8486565
13967772a59a5
1447604c92553
15241540c8c65
hex1312220e39d

1310537606045 has 16 divisors (see below), whose sum is σ = 1641525315840. Its totient is φ = 1002537976704.

The previous prime is 1310537606033. The next prime is 1310537606083. The reversal of 1310537606045 is 5406067350131.

It is a cyclic number.

It is not a de Polignac number, because 1310537606045 - 210 = 1310537605021 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1310537605993 and 1310537606011.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1374905 + ... + 2124014.

It is an arithmetic number, because the mean of its divisors is an integer number (102595332240).

Almost surely, 21310537606045 is an apocalyptic number.

It is an amenable number.

1310537606045 is a deficient number, since it is larger than the sum of its proper divisors (330987709795).

1310537606045 is a wasteful number, since it uses less digits than its factorization.

1310537606045 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3502204.

The product of its (nonzero) digits is 226800, while the sum is 41.

The spelling of 1310537606045 in words is "one trillion, three hundred ten billion, five hundred thirty-seven million, six hundred six thousand, forty-five".

Divisors: 1 5 23 115 3257 16285 74911 374555 3498919 17494595 80475137 402375685 11395979183 56979895915 262107521209 1310537606045