Base | Representation |
---|---|
bin | 111101000011000101… |
… | …0100111110101000000 |
3 | 110112101120200111220112 |
4 | 1322012022213311000 |
5 | 4121443041403100 |
6 | 140120530530452 |
7 | 12320531122556 |
oct | 1720612476500 |
9 | 415346614815 |
10 | 131099950400 |
11 | 50665560151 |
12 | 214a9136a28 |
13 | c493a38a63 |
14 | 64b95d3bd6 |
15 | 36246d9b35 |
hex | 1e862a7d40 |
131099950400 has 42 divisors (see below), whose sum is σ = 322587819390. Its totient is φ = 52439979520.
The previous prime is 131099950339. The next prime is 131099950403. The reversal of 131099950400 is 4059990131.
It can be written as a sum of positive squares in 3 ways, for example, as 44612198656 + 86487751744 = 211216^2 + 294088^2 .
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131099950403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 40967135 + ... + 40970334.
Almost surely, 2131099950400 is an apocalyptic number.
131099950400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131099950400 is an abundant number, since it is smaller than the sum of its proper divisors (191487868990).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131099950400 is an equidigital number, since it uses as much as digits as its factorization.
131099950400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 81937491 (or 81937476 counting only the distinct ones).
The product of its (nonzero) digits is 43740, while the sum is 41.
The spelling of 131099950400 in words is "one hundred thirty-one billion, ninety-nine million, nine hundred fifty thousand, four hundred".
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