1311000121020 has 96 divisors (see below), whose sum is σ = 3740590808640. Its totient is φ = 342955192320.

The previous prime is 1311000120961. The next prime is 1311000121063. The reversal of 1311000121020 is 201210001131.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a junction number, because it is equal to n+sod(n) for n = 1311000120987 and 1311000121005.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 26079510 + ... + 26129730.

It is an arithmetic number, because the mean of its divisors is an integer number (38964487590).

Almost surely, 2^{1311000121020} is an apocalyptic number.

1311000121020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1311000121020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1870295404320).

1311000121020 is an abundant number, since it is smaller than the sum of its proper divisors (2429590687620).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311000121020 is a wasteful number, since it uses less digits than its factorization.

1311000121020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 58495 (or 58493 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 12.

Adding to 1311000121020 its reverse (201210001131), we get a palindrome (1512210122151).

The spelling of 1311000121020 in words is "one trillion, three hundred eleven billion, one hundred twenty-one thousand, twenty".