13110033000040 has 96 divisors (see below), whose sum is σ = 30243689775000. Its totient is φ = 5114568130560.

The previous prime is 13110032999993. The next prime is 13110033000083. The reversal of 13110033000040 is 4000033001131.

It can be written as a sum of positive squares in 12 ways, for example, as 1807889998084 + 11302143001956 = 1344578^2 + 3361866^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13110032999978 and 13110033000023.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 237262336 + ... + 237317584.

Almost surely, 2^{13110033000040} is an apocalyptic number.

13110033000040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13110033000040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15121844887500).

13110033000040 is an abundant number, since it is smaller than the sum of its proper divisors (17133656774960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13110033000040 is a wasteful number, since it uses less digits than its factorization.

13110033000040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 58871 (or 58826 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 13110033000040 its reverse (4000033001131), we get a palindrome (17110066001171).

The spelling of 13110033000040 in words is "thirteen trillion, one hundred ten billion, thirty-three million, forty", and thus it is an aban number.