131102111101013 has 4 divisors (see below), whose sum is σ = 141186888878028. Its totient is φ = 121017333324000.

The previous prime is 131102111100971. The next prime is 131102111101103. The reversal of 131102111101013 is 310101111201131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 14265857418289 + 116836253682724 = 3777017^2 + 10809082^2 .

It is a cyclic number.

It is not a de Polignac number, because 131102111101013 - 2⁶ = 131102111100949 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131102111100982 and 131102111101000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131102111121013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5042388888488 + ... + 5042388888513.

It is an arithmetic number, because the mean of its divisors is an integer number (35296722219507).

Almost surely, 2^{131102111101013} is an apocalyptic number.

131102111101013 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

131102111101013 is a deficient number, since it is larger than the sum of its proper divisors (10084777777015).

131102111101013 is a wasteful number, since it uses less digits than its factorization.

131102111101013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10084777777014.

The product of its (nonzero) digits is 18, while the sum is 17.

Adding to 131102111101013 its reverse (310101111201131), we get a palindrome (441203222302144).

The spelling of 131102111101013 in words is "one hundred thirty-one trillion, one hundred two billion, one hundred eleven million, one hundred one thousand, thirteen".