1311023411 has 4 divisors (see below), whose sum is σ = 1311096024. Its totient is φ = 1310950800.

The previous prime is 1311023383. The next prime is 1311023419. The reversal of 1311023411 is 1143201131.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 1143201131 = 23 ⋅49704397.

It is a cyclic number.

It is not a de Polignac number, because 1311023411 - 2⁶ = 1311023347 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1311023411.

It is not an unprimeable number, because it can be changed into a prime (1311023419) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14156 + ... + 53126.

It is an arithmetic number, because the mean of its divisors is an integer number (327774006).

Almost surely, 2^1311023411 is an apocalyptic number.

1311023411 is a deficient number, since it is larger than the sum of its proper divisors (72613).

1311023411 is an equidigital number, since it uses as much as digits as its factorization.

1311023411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 72612.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 1311023411 is about 36208.0572663047. The cubic root of 1311023411 is about 1094.4690436146.

Adding to 1311023411 its reverse (1143201131), we get a palindrome (2454224542).

The spelling of 1311023411 in words is "one billion, three hundred eleven million, twenty-three thousand, four hundred eleven".