Base | Representation |
---|---|
bin | 1011111011000111101110… |
… | …0000111000010010010000 |
3 | 1201102100000012202021112020 |
4 | 2332301323200320102100 |
5 | 3204244404433412422 |
6 | 43514443330131440 |
7 | 2522121522513120 |
oct | 276617340702220 |
9 | 51370005667466 |
10 | 13110312404112 |
11 | 41a5063626720 |
12 | 1578a49120b80 |
13 | 7413b2b07011 |
14 | 3347848cac80 |
15 | 17b068ddd95c |
hex | bec7b838490 |
13110312404112 has 160 divisors (see below), whose sum is σ = 42226842071040. Its totient is φ = 3405161410560.
The previous prime is 13110312404087. The next prime is 13110312404131. The reversal of 13110312404112 is 21140421301131.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 207827808 + ... + 207890880.
It is an arithmetic number, because the mean of its divisors is an integer number (263917762944).
Almost surely, 213110312404112 is an apocalyptic number.
13110312404112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
13110312404112 is an abundant number, since it is smaller than the sum of its proper divisors (29116529666928).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13110312404112 is a wasteful number, since it uses less digits than its factorization.
13110312404112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 119341 (or 119335 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 24.
Adding to 13110312404112 its reverse (21140421301131), we get a palindrome (34250733705243).
The spelling of 13110312404112 in words is "thirteen trillion, one hundred ten billion, three hundred twelve million, four hundred four thousand, one hundred twelve".
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